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Old 06-22-2011, 09:43 AM   #4
suzeeq
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No because you've got the extra sts in there after the inc rows, so you have to put in the extra sts that would come in the sequence of repeated ones, or the ones before it.

So row 2 becomes - k1 p1 * k1, p4, rep from * to last 2 sts, k2
Row 3 woud be - k1, p1 *k3, p2, rep from * to last 2 sts, k2
then rows 4, 5 and 6 would be as above.

Then row 7 is the same as row 1 with the incs, so the following rows would be -

k1 p2 * k1, p4, rep from * to last 3 sts, k1, p1, k1
and - k1, p21 *k3, p2, rep from * to last 3 sts, k3

See how you're inserting the new sts in there; the end sts will remain the same, but the new sts will start in the end of what would be a previous sequence.
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