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Old 04-06-2012, 08:16 PM   #3
Turning the Heel
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6stsx3needles=18sts to start

row1: 18/3sts per repeat (k2tog, k1)=6groupsx2=12sts
row2: 12/3=4x2=8
row3: 8/3=2.6=5.3

Nope. Seems to me you can end with 8 or 5 but not 6 and therefore you cannot have 2sts per needle.
I guess on row 3 you could omit one k2tog to leave the extra st and end with 6.
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